select c.categories_id, IF(c.categories_image<>'',c.categories_image,'noimage.jpg') as categories_image, cd.categories_name from categories c, categories_description cd where cd.categories_id=c.categories_id and cd.language_id='4' and c.parent_id='5050' and c.categories_status='1' order by c.sort_order, cd.categories_name
MySQL server has gone away2006 - MySQL server has gone away

select count(*) as total from sessions where sesskey = '1a2ro7sui1p5bsh9kandgn37t2'

[TEP STOP]